Two particles are in SHM with same angular frequency and amplitudes A and 2A respectively along same straight line with same mean position. They cross each other at position A/2 distance from mean position in opposite direction. The phase difference between them is :(choose the correct option)
Asked by prabhakar p | 1st May, 2013, 06:28: AM
Expert Answer:
A/2 = 2A sin(wt+phi)
1/4 =sin(2pi/T x T/12+phi)
phase difference=phi=
Answered by | 6th May, 2013, 12:41: PM
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