CBSE Class 11-science Answered
Two oxides of metal contain 27.6% and 30% of oxygen respectively. If the formula of first oxide is M3O4 what is the formula of second oxide.pls explain
Asked by Pramod R | 29 May, 2012, 08:52: AM
Expert Answer
Formula of first oxide = M3O4
let mass of the metal be == x
percentage of metal in M3O4 = (3x/ 3x+64) *100
but % age = (100-27.6) = 72.4 %
so, (3x/ 3x+64)*100 = 72.4
or x = 56.
in 2nd oxide,
oxygen = 30%....so metal = 70%
so, ratio :--
M : O
70/56 : 30/16
1.25 : 1.875
2 : 3
so, 2nd oxide = M2O3
Answered by | 30 May, 2012, 08:51: AM
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