CBSE Class 11-science Answered
Two oxides of a metal contain 27.6% and 30.0% of oxygen respectively. If the formula of the first oxide is M3O4, find that of the second.
Asked by Koushtav Chakrabarty | 19 Jul, 2012, 01:34: PM
Percentage of oxygen=27.6
Precentage of metal=100-27.6=72.4
Formula of the metal oxide=M3O4
Let the atomic mass of the metal= x
Percentage by weight of the metal in the oide M3O4=3x *100/3x+64=72.4
3x=0.724*3x+0.724*64
0.828x=46.336
x=56
The atomic mass of the metal=56
Element Precentage Atomic Mass Atomic ratio Simplest ratio whole no.ratio
M 70 56 70/56=1.25 1.25/1.25=1 2
O 30 16 30/16 1.88/1.25=1.5 3
M2O3
Answered by | 20 Jul, 2012, 01:24: AM
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