Two objects A and B are thrown upwards simultaeneously with the same speed.the mass of A is greater than the mass of B.suppose the air exerts a constant equal force resistance on the two bodies.which object rise to greater height

Asked by JAIBHARGAVA200 | 4th Nov, 2014, 04:52: PM

Expert Answer:

Let mA be the mass of object A and mB be the mass of object B.
Let aA and aB be the acceleration of the two bodies downwards due to the air resistance.
Since the bodies are acted upon by a constant air resistance, from the newton's law we can write that:
begin mathsize 14px style straight a subscript straight A equals straight F over straight m subscript straight A space and space straight a subscript straight B subscript space end subscript equals straight F over straight m subscript straight B Given space that space straight m subscript straight A greater than space straight m subscript straight B Hence space we space can space say space that space straight a subscript straight A less than straight a subscript straight B subscript space end subscript If space straight S subscript straight A space and space straight S subscript straight B space are space the space heights space attained space by space the space objects space straight A space and space straight B space respectively space when space thrown space upwards According space to space the space equation space of space motion : straight S subscript straight A equals ut space minus 1 half straight a subscript straight A straight t squared straight S subscript straight B equals ut space minus 1 half straight a subscript straight B straight t squared As space straight a subscript straight A less than straight a subscript straight B subscript space end subscript space we space get space that : straight S subscript straight A greater than space straight S subscript straight B Hence space we space can space say space that space object space straight A space rise space to space straight a space greater space height space than space object space straight B. end style
 


Answered by Jyothi Nair | 5th Nov, 2014, 10:26: AM

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