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two numbers are such that three times the first added to four times the second is 96 and the excess of four times the first over three times the second is three find the number
Asked by Gangrademohini | 01 Jan, 2020, 10:58: PM
Expert Answer
Let and y be the two numbers
As per the question,
3x+4y=96 ... (i) and
4x=3y+3
i.e. 4x-3y=3 ... (ii)
Multiplying (i) by 3 and (ii) by 4, we have
9x+12y=288 ... (iii)
16x-12y=12 ... (iv)
Adding (iii) and (iv), we have
25x=300
i.e. x=12
Substituting x in (i), we get
3(12)+4y=96
4y=96-36=60
Therefore, y=15.
Answered by Renu Varma | 02 Jan, 2020, 11:09: AM
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