CBSE Class 12-science Answered
two identical thin rings each of radius R are coaxially placed a distance R apart. if Q1 and Q2 are respectively the charges uniformly spread on the two rings the work done in moving a charge q from the centre of one ring to that of the other is
Asked by Gaurav Avhad | 29 Oct, 2010, 02:23: PM
Expert Answer
Dear student
Following is the detailed working out of your query:
Take r as the radius fo each ring & R is the distance of separation between the two centers of the rings.
Work done in moving a unit charge from the cneter of ring 1 to the center of ring 2 will be
W = V2 - V1
So substitute & transpose the terms, we obtain the following expression:
We hope that clarifies your query
Regards
Team
TopperLearning
Answered by | 07 Nov, 2010, 07:22: AM
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