two equal and +ve charges are seperated by distance "l" what is tha potential at the mid point of line joining them
Asked by Atharv Sakalley | 9th May, 2013, 04:55: PM
Expert Answer:
Potential = kq/r where k = 1/4pie0
Here r = I/2
Hence, potential = kq/(I/2) + kq/(I/2)
Potential = 4kq/I
Answered by | 10th May, 2013, 05:46: AM
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