Two dice are thrown simultaneously. Find the probability that the sum of the two numbers appearing on their top is less than or equal to 10.
Asked by Topperlearning User | 4th Apr, 2014, 10:50: AM
Total number of outcomes = 36
Favorable outcomes with the sum as 11 are (5, 6) and (6, 5).
Favourable outcome with the sum as 12 is (6, 6).
P(sum 11) =
P(sum 12) =
P(sum 10) = 1 - [P(sum 11) + P(sum 12)]
Answered by | 4th Apr, 2014, 12:50: PM
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