Two circles intersect each other at A and B. Prove that the angle subtended by the common tangent PQ at A and B are supplementary

Asked by rushabh1234 | 7th Feb, 2019, 10:24: PM

Expert Answer:

angle APQ = Angle PBA......angles in alternate segment
angle AQP = Angle ABQ......angles in alternate segment
also in triangle APQ
angle PAQ  +  angle APQ +  angle AQP = 180
angle PAQ  +  angle PBA +  angle ABQ = 180
angle PAQ  +  angle PBQ = 180

Answered by Arun | 8th Feb, 2019, 11:09: AM