two blocks a and b of mass m(a) and m(b) respectively are kept in contact on a friction less table the experimentar pushes the block from behind so that the blocks accelerate. If the the block a exerts a force F on the block B, what is the force exerted by the experimenter on A?

Asked by abhilasha Jha | 6th Jul, 2011, 03:58: AM

Expert Answer:

Let the force exerted by the experimenter on A is F'. Then, the acceleration produced in the system, a = F' / (ma + mb)
The force on the block B = F = mb x a = mb x F' / (ma + mb)
F' = F (ma + mb)/mb = F (1 + ma/mb)

Answered by  | 6th Jul, 2011, 11:10: AM

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