two blocks a and b of mass m(a) and m(b) respectively are kept in contact on a friction less table the experimentar pushes the block from behind so that the blocks accelerate. If the the block a exerts a force F on the block B, what is the force exerted by the experimenter on A?
Asked by abhilasha Jha
| 6th Jul, 2011,
03:58: AM
Expert Answer:
Let the force exerted by the experimenter on A is F'. Then, the acceleration produced in the system, a = F' / (ma + mb)
The force on the block B = F = mb x a = mb x F' / (ma + mb)
F' = F (ma + mb)/mb = F (1 + ma/mb)
Answered by
| 6th Jul, 2011,
11:10: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change