Two billiard balls are rolling on a flat table.One has a velocity component Vx=1m/s, Vy=(3)1/2 m/s & the other ball has componentsVx=2m/s, Vy=2m/s. If both balls start moving from same point,find angle between their paths.
Asked by akkisara
| 12th Feb, 2012,
06:03: PM
Expert Answer:
For the first ball v x= 1m/s and vy=?3m/s
tan?= v y/ v x = ?3/1= ?3
?= 600
For the second ball, tan?= v y/ v x
=2/2 =1
?=450
Hence, the angle between the paths of two balls =600-450 =150
tan?= v y/ v x = ?3/1= ?3
?= 600
For the second ball, tan?= v y/ v x
=2/2 =1
?=450
Hence, the angle between the paths of two balls =600-450 =150
Answered by
| 12th Feb, 2012,
11:08: PM
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