TRIGONOMETRY
Asked by
| 8th Oct, 2008,
04:29: PM
Expert Answer:
put secA= 1/cosA
LHS = (1-cos4A)cos8A / (1-cos8A) cos4A
= 2sin22A cos8A / 2sin24A cos4A ( 2sin24A cos4A = sin8A)
= 2sin22A cos8A / sin4A sin8A (sin4A = 2sin2A cos2A)
= 2sin22A cos8A / 2sin2A cos2A sin8A
=sin2A cos8A / cos2A sin8A
=tan2A / tan8A
Answered by
| 1st Dec, 2008,
10:10: PM
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