trigonometry.

Asked by khushal305 | 16th Feb, 2010, 02:03: PM

Expert Answer:

tan2 θ + secθ = 5

i.e sec2 θ -1 + secθ = 5

i.e sec2 θ  + secθ -6 = 0

i.e sec2 θ  + 3secθ - 2 secθ - 6 = 0

i.e secθ (secθ +3) -2(secθ +3)=0

i.e (secθ-2)(secθ+3) = 0

So, secθ  = 2 or -3

Answered by  | 16th Feb, 2010, 02:31: PM

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