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CBSE Class 10 Answered

trigonometry
Asked by | 06 Mar, 2008, 01:48: PM
Expert Answer

sinθ= a/b,  this gives  cosθ= sq root of ( b square- a square) / b.

so secθ+tanθ = b/ sq root of ( b square- a square)  + a/b.

Answered by | 12 Mar, 2008, 10:27: AM
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