Asked by  | 6th Mar, 2008, 01:48: PM

Expert Answer:

sinθ= a/b,  this gives  cosθ= sq root of ( b square- a square) / b.

so secθ+tanθ = b/ sq root of ( b square- a square)  + a/b.

Answered by  | 12th Mar, 2008, 10:27: AM

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