CBSE Class 10 Answered
trigonometry
Asked by | 04 Jul, 2008, 04:28: PM
Expert Answer
cosB(3-4cos2B)
=cosB[3-4(1-sin2B)]
=cosB[3-4 - 4 sin2B]
=cos B [-1 -4(1/4)]
= cosB[-1 +1 ]
= 0
Answered by | 15 Jul, 2008, 04:28: PM
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