Trigonometry
Asked by | 2nd Dec, 2008, 02:46: PM
5sin(90-50)o / 7cos50o - 3cos53osec(90- 53)ocos60o / 7tan(90- 75)ocot53otan75o
=5scos50o / 7cos50o - 3cos53ocosec53)ocos60o / 7cot 75)ocot53otan75o
=5 / 7 - 3cos53ocosec53)ocos60o / 7cot 75)ocot53otan75o
=5 / 7 - 3cot53ocos60o / 7cot53o
=5 / 7 - 3cos60o / 7
=5 / 7 - 3 / 14
=10 / 14 - 3 / 14
=7/14= 1/2
Answered by | 2nd Dec, 2008, 03:20: PM
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