Trigonometry

Asked by  | 2nd Dec, 2008, 02:46: PM

Expert Answer:

5sin(90-50)o / 7cos50o  -  3cos53osec(90- 53)ocos60o / 7tan(90- 75)ocot53otan75o

=5scos50o / 7cos50o  -  3cos53ocosec53)ocos60o / 7cot 75)ocot53otan75o

=5 / 7  -  3cos53ocosec53)ocos60o / 7cot 75)ocot53otan75o

=5 / 7  -  3cot53ocos60o / 7cot53o

=5 / 7  -  3cos60o / 7

=5 / 7  -  3 / 14

=10 / 14  -  3 / 14

=7/14= 1/2

Answered by  | 2nd Dec, 2008, 03:20: PM

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