CBSE Class 10 Answered
trigonometry
Asked by haynes | 07 Apr, 2009, 09:34: PM
Expert Answer
Let AB be the tower.C and D be the two points 4m and 9m away respectively from B.
Let AB=h
Given,
if angle ACB=x
then angle ADB=90-x
So,
tan x=AB/4...(i)
tan(90-x)=AB/9...(ii)
so ,
tanx =AB/4..(iii)
and
cot x= AB/9....(iv)
multiplying (iii) and (iv)
we get,
AB*AB=36
So,
AB=6
So the height of the tower is 6m.
Note that we have used the fact that
tanx*cotx=1
and also that whichever angle is x doesn't matter as long as you take the other angle as its complimentary angle
Answered by | 08 Apr, 2009, 08:36: AM
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