Trigonometry

Asked by  | 1st Oct, 2008, 08:44: AM

Expert Answer:

sinx + sin2x + sin3x = 0

sinx + sin3x + sin2x = 0

2 sin(x+3x)/2 cos (x-3x)/2 +sin2x= 0

2sin2xcos(-x) + sin 2x =0

sin2x(2cosx +1) = 0

sin2x = 0 or cos x = -1/2 = cos (  - /3)

2x = n  or x = 2n(  - /3)

x = n /2or x = 2n(  - /3)

Answered by  | 1st Oct, 2008, 08:54: AM

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