Trigonometry question - (sinA + 1 - cosA)/(cosA - 1 + sinA) = (1+sinA)/cosA

Asked by ash.au94 | 23rd Aug, 2009, 01:11: PM

Expert Answer:

Consider LHS (sinA + 1 - cosA)/(cosA - 1 + sinA) 

Dividing Num and denominator by cos A

we get (tan A +sec A-1)/(1-sec A + tan A)

Multiplying and dividing by tan A-Sec A

((tan 2 A-sec2 A)- (tan A-Sec A))/(tan A-sec A+1)(tan A-sec A)

= 1/(sec A - tan A) = cos A/(1-sin A)

= (1+sin A)/cos A

Answered by  | 24th Aug, 2009, 11:16: AM

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