Trigonometry question - (sinA + 1 - cosA)/(cosA - 1 + sinA) = (1+sinA)/cosA
Asked by ash.au94 | 23rd Aug, 2009, 01:11: PM
Expert Answer:
Consider LHS (sinA + 1 - cosA)/(cosA - 1 + sinA)
Dividing Num and denominator by cos A
we get (tan A +sec A-1)/(1-sec A + tan A)
Multiplying and dividing by tan A-Sec A
((tan 2 A-sec2 A)- (tan A-Sec A))/(tan A-sec A+1)(tan A-sec A)
= 1/(sec A - tan A) = cos A/(1-sin A)
= (1+sin A)/cos A
Answered by | 24th Aug, 2009, 11:16: AM
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