CBSE Class 11-science Answered
Trigonometric Ratios of Compound Angles
Asked by | 23 Mar, 2008, 09:29: PM
Expert Answer
1/ tan3A-tanA - 1/cot3A-cotA = cot2A
1/ 1/ cot3A - 1/ cotA - 1/ cot3A - cotA
cotA cot3A/ cotA - cot3A - 1/ cotA - cot3A
1 + cotA cot3A / cotA - cot3A
(1 + 1/ tanA.tan3A )/ (1/ tanA - 1/ tan3A)
(tanA tan3A +1)/ (tan3A - tanA )
{ tanA ( 3 tanA - tan3A/ 1-3tan2A) + 1} / {( 3 tanA - tan3A)/1 - 3tan2A} - tanA
(1 - tan 4 A)/ (2 tan A + 2tan3A) = (1 - tan2A)/ 2 tanA
= ( 1 - tan2A)( 1+tan2A)/ 2tanA ( 1+tan2A) = ( 1 - tan2A)/ 2tanA
= (cot2 A - 1)/2 cot2A = cot2A
Proved
Answered by | 11 Jun, 2008, 05:05: PM
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