trigo/
Asked by kanishkaaggarwal | 25th Nov, 2009, 11:36: AM
cosA = tanA
cosA = sinA/cosA
cos2A = sinA
1 - sin2A = sinA
sin2A + sinA - 1 = 0
sinA = [-1±(1+4)]/2 = [-1±
5]/2
cos2A = 1 - sin2A = 1 - [-1±5]2/4 = (4-1-5±2
5)/4 = (-1±
5)/2
Regards,
Team,
TopperLearning.
Answered by | 25th Nov, 2009, 01:59: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change