trigo/
Asked by kanishkaaggarwal | 25th Nov, 2009, 11:36: AM
Expert Answer:
cosA = tanA
cosA = sinA/cosA
cos2A = sinA
1 - sin2A = sinA
sin2A + sinA - 1 = 0
sinA = [-1±
(1+4)]/2 = [-1±5]/2
cos2A = 1 - sin2A = 1 - [-1±5]2/4 = (4-1-5±25)/4 = (-1±5)/2
Regards,
Team,
TopperLearning.
Answered by | 25th Nov, 2009, 01:59: PM
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