# CBSE Class 10 Answered

**trigo...**

Asked by deepitapai | 09 Mar, 2009, 12:49: PM

Expert Answer

sin^{6}θ+cos^{6}θ =(sin^{2} θ)^{3}+(cos^{2}θ)^{3 }=(sin^{2} θ+cos^{2}θ)(sin^{4} θ+cos^{4}θ-sin^{2} θcos^{2}θ)=(1)((sin^{2} θ+cos^{2}θ)^{2} -2sin^{2} θcos^{2}θ-sin^{2} θcos^{2}θ)=1-3sin^{2} θcos^{2}θ

Answered by | 13 Mar, 2009, 01:34: AM

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