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CBSE Class 10 Answered

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Asked by deepitapai | 09 Mar, 2009, 12:49: PM
Expert Answer

sin6θ+cos6θ =(sin2 θ)3+(cos2θ)=(sin2 θ+cos2θ)(sin4 θ+cos4θ-sin2 θcos2θ)=(1)((sin2 θ+cos2θ)2 -2sin2 θcos2θ-sin2 θcos2θ)=1-3sin2 θcos2θ

Answered by | 13 Mar, 2009, 01:34: AM
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