trigo...

Asked by deepitapai | 9th Mar, 2009, 12:49: PM

Expert Answer:

sin6θ+cos6θ =(sin2 θ)3+(cos2θ)=(sin2 θ+cos2θ)(sin4 θ+cos4θ-sin2 θcos2θ)=(1)((sin2 θ+cos2θ)2 -2sin2 θcos2θ-sin2 θcos2θ)=1-3sin2 θcos2θ

Answered by  | 13th Mar, 2009, 01:34: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.