CBSE Class 10 Answered
triangles
Asked by | 12 Mar, 2009, 09:53: AM
Expert Answer
let side BD be 'x'
then, DC=a-x
from the angle bisecting property in ΔABC, we get,
AB/BD=AC/CD,then
c/x=b/a-x
ca-cx=bx
ca=bx+cx
x=ac/b+c
so,BD=ac/b+c;
& DC= a-x = a-(ac/b+c)
= (ab+ac-ac)/b+c
so, DC = ab/b+c
Answered by | 29 May, 2009, 11:52: PM
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