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CBSE Class 10 Answered

triangles
Asked by | 12 Mar, 2009, 09:53: AM
Expert Answer

let side BD be 'x'

then, DC=a-x

from the angle bisecting property in ΔABC, we get,

AB/BD=AC/CD,then

c/x=b/a-x

ca-cx=bx

ca=bx+cx

x=ac/b+c

so,BD=ac/b+c;

& DC= a-x = a-(ac/b+c)

        = (ab+ac-ac)/b+c

so, DC = ab/b+c

Answered by | 29 May, 2009, 11:52: PM
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