CBSE Class 10 Answered
triangles
Asked by suchet_r | 05 Dec, 2009, 10:15: PM
Expert Answer
In triangle ADC and triangle ACB
ADC = ACB (Both 90o)
DAC is common
ADC ACB (By AA corollary)
So, CD/ AD = CB/ CA ..........(1) [By cpct]
In triangle BDC and triangle ACB
BDC = ACB (Both 90o)
DBC is common
BDC ACB (By AA corollary)
So, BD/ CD = CB/ CA ..........(2) [By cpct]
Multiplying (1) and (2), we get
CB2 / CA2 = BD / AD
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