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CBSE Class 10 Answered

triangles
Asked by | 13 Feb, 2009, 10:25: PM
Expert Answer

A,B and C are the interior angles of a triangle.

So,

 A +  B+  C= 180

Now,

sin[( B+C)/2]=sin [(180-A)/2]

=sin[90-(A/2)]

=cos(A/2)

Answered by | 14 Feb, 2009, 05:33: PM
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