Triangle abc is right angled at c. m is the mid point of ab. prove that cm = 1/2 of ab
Asked by 100.akash | 13th Sep, 2008, 12:04: PM
we know that any triangle which is inscribed in a semicircle is a right angle triangle.
let a and b be the ends of the diameter and c be the point on the periphery.
so according to question m is the center of the circle
so we have cm = R (radius of the circle)
and ab= 2R
clearly cm = 1/2 ab
Answered by | 13th Sep, 2008, 10:08: PM
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