Train starting from rest attains a velocity of 70 km/h in 10 minutes. Assuming that the acceleration is uniform, find the acceleration and the distance travelled by the train while it attained this velocity.
By third equation of motion,the S= 5905m
By second equation of motion, the S= 5600m
Why is the difference in answer?
Asked by Ashwin Kumar | 18th May, 2014, 02:49: PM
Answered by Romal Bhansali | 19th May, 2014, 11:03: AM
- plz solve urgently dear experts :
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