TP and T'Q are parallel tangents to a cicle with radius r , with T and T' the points of tangency.PT''Q is a third tangent with T'' as point of tangency.the centre of the circle is o and it is joined to T'' to form radius r.if TP=4,T'Q=9 then find r
Asked by Ashrene | 26th Oct, 2012, 05:05: PM
Since from P the tangents are PT and PT''
So, PQ=PT''+QT'' = 9+4 =13
Now, TT'=r+r = 2r
And The difference of T'Q-PT= 9 - 4 = 5
So, PQ2=TT'2 + (T'Q- TP)2
or r=6 is the answer.
Answered by | 9th Nov, 2012, 05:00: PM
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