total surface areas n volumes

let the height be h and radius be r.

volume of  the cylinder= pi*r²*h

and volume of the cone = (1/3)*pi*r²*h

so the voluem of the remaining solid will be = pi*r²*h- (1/3)*pi*r²*h = (2/3)*pi*r²*h

surface area of remaining solid = surface area of top+surface area of hollow cone + surface area of cylindrical part

=pi*r² + pi*r*l + 2*pi*r*h

where l is equal to (r²+h²) .

put the value of h=24cm and r=D/2 = 7cm