topper test question
Asked by varunsinghal2011 | 8th May, 2010, 10:36: AM
Expert Answer:
Frictional force = (coefficient of friction)(Normal reaction)
= μ(mgcosθ)
= (0.7)(2x9.8x
3/2)
= 11.9 N
Regards,
Team,
TopperLearning.
Answered by | 8th May, 2010, 11:48: AM
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