topper test question

Asked by varunsinghal2011 | 8th May, 2010, 10:36: AM

Expert Answer:

Frictional force = (coefficient of friction)(Normal reaction)

                        = μ(mgcosθ)

                       = (0.7)(2x9.8x3/2)

                       = 11.9 N

Regards,

Team,

TopperLearning.

 

Answered by  | 8th May, 2010, 11:48: AM

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