to find value.

Asked by Harshal Saptarshi | 5th Sep, 2010, 11:21: PM

Expert Answer:

Dear Student
Consider x = a sec Θ+b tan Θ
y =  b sec Θ+a tan Θ
Squaring and subtracting we get
x2-y2 =  a2 sec2 Θ+b2 tan2 Θ+2absecΘtanΘ- b2 sec2 Θ-a2 tan2 Θ-2absecΘtanΘ
=a2 ( sec2 Θ - tan2Θ) +b2 ( tan2Θ-sec2 Θ)
=a2-b2

Answered by  | 6th Sep, 2010, 11:18: AM

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