to find radius
Asked by meghapte | 18th Jan, 2010, 09:27: PM
Let d1 and d2 be the diagonal of the rhombus OPQR.
PQR the points that lies on the circle having centre O.
Now Area of rhombus = 1/2 (d1.d2) = 323
⇒ d1.d2 = 643 ....................(1)
Now, since the diagonals of rhombus are perpedicular bisector of each other.
Also, the side of the parallelogram is equal to the smaller diagonal d2.
⇒ (d1/2)2 +(d2/2)2 = d2
⇒ d12 + d22 = 4d22
⇒ d1 = 3 d2
Substituting in equation (1), we get d2 = 8
So, the radius of the circle is 8 cm.
Answered by | 19th Jan, 2010, 10:06: AM
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