to find radius

Asked by meghapte | 18th Jan, 2010, 09:27: PM

Expert Answer:

Let d1 and d2 be the diagonal of the rhombus OPQR.

PQR the points that lies on the circle having centre O.

Now Area of rhombus = 1/2 (d1.d2) = 323

⇒ d1.d2 = 643  ....................(1)

Now, since the diagonals of rhombus are perpedicular bisector of each other.

Also, the side of the parallelogram is equal to the smaller diagonal d2.

(d1/2)2 +(d2/2)2 = d2

⇒ d12 + d22 = 4d22  

⇒ d1 = 3 d2

Substituting in equation (1), we get d2 = 8

So, the radius of the circle is 8 cm.

Answered by  | 19th Jan, 2010, 10:06: AM

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