CBSE Class 10 Answered
to find radius
Asked by meghapte | 18 Jan, 2010, 09:27: PM
Expert Answer
Let d1 and d2 be the diagonal of the rhombus OPQR.
PQR the points that lies on the circle having centre O.
Now Area of rhombus = 1/2 (d1.d2) = 323
⇒ d1.d2 = 643 ....................(1)
Now, since the diagonals of rhombus are perpedicular bisector of each other.
Also, the side of the parallelogram is equal to the smaller diagonal d2.
⇒ (d1/2)2 +(d2/2)2 = d2
⇒ d12 + d22 = 4d22
⇒ d1 = 3 d2
Substituting in equation (1), we get d2 = 8
So, the radius of the circle is 8 cm.
Answered by | 19 Jan, 2010, 10:06: AM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT