CBSE Class 10 Answered
to find no. of sides
Asked by meghapte | 17 Jan, 2010, 03:35: PM
Expert Answer
Sum of interior angles of a polygon = 180(n-2) ........where n is the number of sides.
The interior angles are in AP and smallest angle is 120 i.e. first term of AP.
Sum of interior angles =n(2a+(n-1)d)/2
180(n-2) = n(240+(n-1)5)/2
5n2-125n+720 = 0
n2-25n+144 = 0
The polygon can have 9 or 16 sides.
Regards,
Team,
TopperLearning.
Answered by | 17 Jan, 2010, 04:04: PM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT
