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CBSE Class 12-science Answered

to calculate the no.of atoms initially present and the activity.
Asked by Upasana | 29 Mar, 2012, 07:55: PM
answered-by-expert Expert Answer
Ans =(i) 1.2× 1020 = Number of atoms present initially. (ii) 1.55 × 1014 disintegrations/second
Answered by | 04 Apr, 2012, 04:48: PM

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CBSE 12-science - Physics
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CBSE 12-science - Physics
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CBSE 12-science - Physics
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CBSE 12-science - Physics
55Cs124(Z=55,A=124) has a half life of 30.8s. (a) If we have 7.8 microgram initially, how many nuclei are presents? How many are present 2 min later? (b) What is the activity at this time? (c) After how much time will the activity drop to less than about 1 per second?
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CBSE 12-science - Physics
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CBSE 12-science - Physics
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CBSE 12-science - Physics
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