Three identical cells, each of emf 2 V and internal resistance 0.2 ohm are connected in series to an external resistor of 5.4 ohm. Calculate the current in the circuit.

Asked by Topperlearning User | 24th Apr, 2015, 03:37: PM

Expert Answer:

Net emf of the cell = 3 x 2 = 6 V

Total resistance of the circuit = 0.2 + 0.2 + 0.2 + 5.4 = 6 ohm

Answered by  | 24th Apr, 2015, 05:37: PM