three faraday of electricity is passed through molten Al2O3 ,aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells .The moles of Al , Cu , Na deposited on cathode will be in ratio of :-

Asked by thakurpratyush5 | 30th Jun, 2015, 05:15: PM

Expert Answer:

Al3+ + 3e → Al

3F are required for 1 mole. So 3F will produce 1 mole.

 

Cu2+ + 2e → Cu

2F are required for 1 mole. So 3F will produce 1.5 moles.

 

Na+ + e → Na

F is required for 1 mole. So 3F will produce 3 moles.

 

Hence, ratio will be 1 mole : 1.5 mole : 3 mole

Answered by Arvind Diwale | 1st Jul, 2015, 12:27: PM