this one plz

Asked by  | 22nd Jun, 2009, 11:11: PM

Expert Answer:

Let the three parts be

a-d,a,a+d ( where d>0)

Their sum is 54(given)

So,

3a=54

So,

a=18

 

Next it's given that the

five times smallest part exceeds the largest by 6

So,

5(a-d)=(a+d)+6

i.e.

4a=6d+6

i.e.

2a=3d+3

Substituting,

a=18,

We get,

36=3d+3

So,

d=11

So, the three required parts of 54 are

7,18,29

 

Answered by  | 23rd Jun, 2009, 01:20: AM

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