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CBSE Class 8 Answered

5 over 7 x space plus space fraction numerator 3 over denominator 2 space end fraction space equals 2 over 7 x space minus 1 space  
therefore , what is the value of x in the above equation?
Asked by diya_shukl | 27 Apr, 2015, 06:03: PM
answered-by-expert Expert Answer
fraction numerator 5 x over denominator 7 end fraction plus 3 over 2 equals fraction numerator 2 x over denominator 7 end fraction minus 1 rightwards double arrow fraction numerator 5 x over denominator 7 end fraction minus fraction numerator 2 x over denominator 7 end fraction equals negative 1 minus 3 over 2 rightwards double arrow fraction numerator 5 x minus 2 x over denominator 7 end fraction equals negative open parentheses fraction numerator 2 plus 3 over denominator 2 end fraction close parentheses rightwards double arrow fraction numerator 3 x over denominator 7 end fraction equals negative 5 over 2 rightwards double arrow x equals negative fraction numerator 5 cross times 7 over denominator 2 cross times 3 end fraction therefore x equals negative 35 over 6 T h e space v a l u e space o f space x space i s space minus 35 over 6
Answered by Prasenjit Paul | 28 Apr, 2015, 09:13: AM

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