The wave length of photons emitted by electron transition between two similar levels in H and He^+ are lambda1 and lambda2 respectively. Then lambda2=lambda1/4.......plzz tell how ???

Asked by Harshal Saptarshi | 9th Aug, 2010, 12:00: AM

Expert Answer:

lambda1 - H
lambda2 - He+
m2 - mass of He+ = 4
m1 = mass of H = 1
 
lambda1 = h/m1v
lambda2 = h/m2v
 
(lambda1/lambda2) = (m2/ m1)
 
(lambda1/lambda2) = (4/1)
 
lambda2=lambda1/4

Answered by  | 9th Aug, 2010, 02:28: PM

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