the vertices of a triangle are A (1,2 , B (5,7) C(11 , 13). find the length of the median passing through the vertices A 

Asked by tarjindersingh55 | 2nd Oct, 2017, 11:54: AM

Expert Answer:

begin mathsize 16px style Let space AD space be space the space median space through space the space vertex space straight A space of space triangle space ABC.
Then comma space straight D space is space the space mid minus point space of space BC.
So comma space the space coordinates space of space straight D space equals space open parentheses fraction numerator 5 plus 11 over denominator 2 end fraction comma space fraction numerator 7 plus 13 over denominator 2 end fraction close parentheses equals open parentheses 16 over 2 comma space 20 over 2 close parentheses equals open parentheses 8 comma space 10 close parentheses
therefore space AD equals square root of open parentheses 1 minus 8 close parentheses squared plus open parentheses 2 minus 10 close parentheses squared end root equals square root of 49 plus 64 end root equals square root of 113 space units end style

Answered by Rashmi Khot | 3rd Oct, 2017, 09:29: AM