The velocity of the particle is given by v = 4t2 + 7 cm/s. Find the velocity of the particle during the time interval t1 = 2s and t2 = 4s also find the average acceleration during the same interval of time.

Asked by Topperlearning User | 17th Apr, 2014, 02:07: PM

Expert Answer:

v = 4t2 + 7

When t1 = 2s, v1 = 4(2)2 + 7 = 23 cm/s
When t2 = 4s, v2 = 4(4)2 + 7 = 71 cm/s
Change in velocity = v2 – v1 = 71 – 23 = 48 cm/s
Average acceleration = 

Answered by  | 17th Apr, 2014, 04:07: PM