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The value of k for which x=-2is afoot of a square of a quadratic equation kx square +x-6=0
Asked by ashleshathakur124 | 20 Oct, 2019, 06:02: PM Expert Answer

if -2 is root of equation kx²+x-6 then

F(-2)=0

F(x)= kx²+x-6

0  = k(-2)²+(-2)-6

0  = 4k-2-6

0  = 4k-8

8  = 4k

8/4 = k

2 = k

Therefore , the value of k is 2

Answered by Renu Varma | 22 Oct, 2019, 08:58: AM

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