CBSE Class 10 Answered
The value of k for which x=-2is afoot of a square of a quadratic equation kx square +x-6=0
Asked by ashleshathakur124 | 20 Oct, 2019, 06:02: PM
Expert Answer
if -2 is root of equation kx²+x-6 then
F(-2)=0
F(x)= kx²+x-6
0 = k(-2)²+(-2)-6
0 = 4k-2-6
0 = 4k-8
8 = 4k
8/4 = k
2 = k
Therefore , the value of k is 2
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