1. The value of k for which x=-2is afoot of a square of a quadratic equation kx square +x-6=0

Asked by ashleshathakur124 | 20th Oct, 2019, 06:02: PM

Expert Answer:

if -2 is root of equation kx²+x-6 then 

F(-2)=0

F(x)= kx²+x-6

    0  = k(-2)²+(-2)-6

    0  = 4k-2-6

    0  = 4k-8

    8  = 4k

    8/4 = k

     2 = k

Therefore , the value of k is 2

 

 

 

Answered by Renu Varma | 22nd Oct, 2019, 08:58: AM