THE VALUE OF GROUND  STATE ENERGY OF HYDROGEN ATOM IS -13.6eV

WHAT DOES THE NEGATIVE SIGN SIGNIFY AND HOW MUCH ENERGY IS REQUIRED TO TAKE AN ELECTRON IN THIS ATOM FROM GROUND STATE TO THE FIRST EXCITED STATE ?

Asked by pardeepkumar2281 | 28th Feb, 2019, 07:24: PM

Expert Answer:

It is total energy of the electron in its ground state in hydrogen atom. As from the study from chemistry for a atom be stable its energy must be low otherwise higher energy of an atom can lead to instability of an atom.
Total energy of electron in an orbit is addition of potential as well as kinetic energy. Kinetic energy can never be negative but potential energy can take negative value. Negative values of potential energy means more the atom will be stable.
 
 
Energy required = 13.6 (1/1 - 1/4) = (13.6×3)/4 = 10.2eV.

Answered by Ankit K | 28th Feb, 2019, 10:21: PM