The two ends of a train moving with uniform acceleration passes a certain point with velocities 6km/hr and 8km/hr respectively.What is the velocity with which the middle point of the train passes the same point?

Asked by DIVYANSHU VADEHRA | 6th Apr, 2013, 10:49: AM

Expert Answer:

Initial Velocity = 6 km/hr

Final Velocity = 8 km/hr


v2 = u2+2as

8= 62+2as

64 = 36+2as

28 = 2as

as = 14 ..........1)

Middle Point = distance = s/2

v2 = u2+2as

v2 = 62+2*a*s/2


v2 = 62+as

Substitute as from equation 1)

v2 = 62+14

v= 50

v = 5(2)1/2 km/h


Answered by  | 6th Apr, 2013, 12:35: PM

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