the time taken for the completion of 3/4th of a reaction to complete is?

Asked by  | 20th Jun, 2013, 04:39: PM

Expert Answer:

t /2 = .693 / k.     for half life of the reaction.
t = 2.303 /k      log  a / (a-x);  when x = 3 /4 a, t = t/2.
t2 = 2.303 /k  log    a / a - 3/4a
or 2.303 x 2 /k   log  2
2x 2.303 x .30 /k 
2x.693 /k   =2xt1
 
time taken for 3  / 4 of a reaction is twice of the half period in a first order reaction.

Answered by  | 21st Jun, 2013, 01:05: AM

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