The three blocks of mass 4 kg, 5 kg, and 6 kg are suspended with the string, which is passed over a pulley. Calculate the tension T1, T2, and T3 when the whole system is moving with an acceleration of 5 m/s2.

Asked by Topperlearning User | 5th Jun, 2014, 05:14: PM

Expert Answer:

When the system is moving in the upward direction with acceleration 5 m/s2

T1 - (m1 + m2 + m3) g = (m1 + m2 + m3) a

T1 = (m1 + m2 + m3) (a + g)
 
T1  = (4 + 5 + 6) × (5 + 9.8) =  222 N
 
Consider the free body diagram of block of mass m2 and m3.
T2 - (m2 + m3) g = (m2 + m3) a
T2 = (m2 + m3) (a + g)
T2 = (5 + 6) (5 + 9.8) = 162.8 N
 
Considering the free body diagram of mass m3
T3 - m3 g = m3 a
T3 = m3 (a + g)
T3 = 6 × 14.8 = 88.8 N

Answered by  | 5th Jun, 2014, 07:14: PM

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