the tangent to y=a(x^2)+bx+7/2 at(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10. Find the value of a and b.
Asked by rohit varshney
| 7th Apr, 2011,
03:35: PM
Expert Answer:
Dear student
You asked the question:
The tangent to
at (1,2) is parallel to the normal at the point (-2,2) on the curve
. Find the value of a and b.
Sol.
To solve this we equate the slope of tangent and normal of the corresponding curves.
Consider
Hope it resolve your quarry.
Regards
Team Topper



Answered by
| 7th Apr, 2011,
12:29: PM
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