the tangent to y=a(x^2)+bx+7/2 at(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10. Find the value of a and b.

Asked by rohit varshney | 7th Apr, 2011, 03:35: PM

Expert Answer:

Dear student
You asked the question:
The tangent to at (1,2) is parallel to the normal at the point (-2,2) on the curve . Find the value of a and b.
Sol.
To solve this we equate the slope of tangent and normal of the corresponding curves.
Consider
  
Hope it resolve your quarry.
Regards
Team Topper

Answered by  | 7th Apr, 2011, 12:29: PM

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