CBSE Class 12-science Answered
the tangent to y=a(x^2)+bx+7/2 at(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10. Find the value of a and b.
Asked by rohit varshney | 07 Apr, 2011, 03:35: PM
Expert Answer
Dear student
You asked the question:
The tangent to 
at (1,2) is parallel to the normal at the point (-2,2) on the curve 
. Find the value of a and b.
at (1,2) is parallel to the normal at the point (-2,2) on the curve . Find the value of a and b.Sol.
To solve this we equate the slope of tangent and normal of the corresponding curves.
Consider
Hope it resolve your quarry.
Regards
Team Topper
Answered by | 07 Apr, 2011, 12:29: PM
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