the tangent to y=a(x^2)+bx+7/2 at(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10. Find the value of a and b.

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You asked the question:

The tangent to at (1,2) is parallel to the normal at the point (-2,2) on the curve . Find the value of a and b.

Sol.

To solve this we equate the slope of tangent and normal of the corresponding curves.

Consider

  

Hope it resolve your quarry.

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