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The sum the digits of two digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54,find the original number.
Asked by firstid121 | 04 Mar, 2019, 12:25: PM
Let the digit at the ten's place be x.
Given : The sum the digits of two digit number is 12.

→ the digit at the unit's place = 12 - x
→ Original number = 10x +(12 - x) = 9x + 12

If the new number formed by reversing the digits is greater than the original number by 54.
[10(12 - x) + x]- [10x +(12 - x)] = 54

After solving, we get
x = 3

Therefore original number = 9x + 12 = 9 × 3 + 12  = 39
Answered by Yasmeen Khan | 04 Mar, 2019, 05:19: PM

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