The sum of the first three terms of an AP is 33. If the product of the first and the third term exceeds the second term by 29, find the AP.

Asked by godson babuji | 6th Nov, 2014, 12:52: AM

Expert Answer:

L e t space a minus d comma space a space a n d space a plus d space b e space t h e space f i r s t space t h r e e space t e r m s space o f space t h e space A P. G i v e n space t h a t space t h e space s u m space o f space t h e space f i r s t space t h r e e space t e r m s equals a minus d plus a plus a plus d equals 33 T h a t space i s comma space 3 a equals 33 rightwards double arrow a equals 11 A l s o space g i v e n space t h a t space t h e space p r o d u c t space o f space t h e space f i r s t space a n d space t h e space t h i r d space t e r m space e x c e e d s space t h e space s e c o n d space t e r m space b y space 29. rightwards double arrow open parentheses a minus d close parentheses cross times open parentheses a plus d close parentheses equals 11 plus 29 rightwards double arrow a squared minus d squared equals 40 rightwards double arrow 11 squared minus d squared equals 40 rightwards double arrow d squared equals 121 minus 40 rightwards double arrow d squared equals 81 rightwards double arrow d equals 9 T h u s space t h e space r e q u i r e d space P space i s space comma space 11 minus 9 comma space 11 comma space 11 plus 9 equals 2 comma 11 comma 20

Answered by Vimala Ramamurthy | 6th Nov, 2014, 08:48: AM

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