the sum of squares of two no's is 117. the square of smaller no. is four times the square of the bigger no. Find the no's.

let the numbers be x and y  and x

ATQ,

x²+y²=117...(i)

and

x²=4y..(ii)

substituting from (ii) into (i) we get,

y²+4y=117

y²+4y-117=0

(y-9)(y+13)=0

y=9, y=-13

y=9,so x=6

y=-13 can't be accepted as eqn (ii) doesn't get satisfied with it.

So the numbers are

x=6, y=9